-2y^2-4y-2=0

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Solution for -2y^2-4y-2=0 equation: 



-2y^2-4y-2=0

a = -2; b = -4; c = -2;
Δ = b2-4ac
Δ = -42-4·(-2)·(-2)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{4}{-4}=-1$

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